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Index Entry
I can take that one-eighth octahedron which is sitting on top of the one-quarter tetrahedron and I can slice it along its three vertexial edges towards the opposite mid-edge, slice it with a knife and break it up into six parts. Then I can fold it back disclosing the one-quarter tetrahedrons so that each of these 8 Particles is one-sixth of o volume which is the same as that of the one-quarter tetrahedron. It is a space between the outer surface and the one-quarter tetrahedron.
